A number is decreased by 10% and then increased by 10%. The number so obtained is 10 less than the original number. What was the oiginal number ?
Correct Answer: Option A
Let the original number be x.
Final number obtained = 110% of (90% of x) =(110 \(\div\) 100 \(\times\) 90 \(\div\) 100 \(\times\) x) = (99 \(\div\) 100)x.
x-(99 \(\div\) 100)x=10
=> x =1000
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